1000x^2+1800x-800=0

Solution for 1000x^2+1800x-800=0 equation:

1000x^2+1800x-800=0

a = 1000; b = 1800; c = -800;
Δ = b2-4ac
Δ = 18002-4·1000·(-800)
Δ = 6440000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6440000}=\sqrt{40000*161}=\sqrt{40000}*\sqrt{161}=200\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1800)-200\sqrt{161}}{2*1000}=\frac{-1800-200\sqrt{161}}{2000}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1800)+200\sqrt{161}}{2*1000}=\frac{-1800+200\sqrt{161}}{2000}
$